{"id":1286,"date":"2023-07-12T10:46:03","date_gmt":"2023-07-12T10:46:03","guid":{"rendered":"https:\/\/headwaytobiology.com\/?page_id=1286"},"modified":"2025-01-02T11:43:02","modified_gmt":"2025-01-02T11:43:02","slug":"ch-14-respiration-in-plants","status":"publish","type":"page","link":"https:\/\/headwaytobiology.com\/?page_id=1286","title":{"rendered":"Ch 14 \u2013 Respiration in\u00a0Plants"},"content":{"rendered":"\t\t
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Respiration in Plants (Glycolysis)<\/h2>\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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1. Which of the following statements about glycolysis is correct?<\/p><\/td><\/tr><\/tbody><\/table>

A) Produces pyruvate<\/p><\/td><\/tr>

C) Occurs in the cytoplasm<\/p><\/td><\/tr>

B) Can occur anaerobically<\/p><\/td><\/tr>

D) All of the above<\/p><\/td><\/tr><\/tbody><\/table>

2. Arrange the following intermediates of glycolysis in sequence:<\/p><\/td><\/tr><\/tbody><\/table>

A) Glucose \u2192 G-6-P \u2192 F-1,6-BP \u2192 PEP\u2192 \u00a0Pyruvate<\/p><\/td><\/tr>

C) Glucose \u2192 F-6-P \u2192 F-1,6-BP \u2192 PEP \u2192 Pyruvate<\/p><\/td><\/tr>

B) Glucose \u2192 G-6-P \u2192 F-1,6-BP \u2192 Pyruvate \u2192 PEP<\/p><\/td><\/tr>

D) G-6-P \u2192 Glucose \u2192 F-1,6-BP \u2192 PEP \u2192 Pyruvate<\/p><\/td><\/tr><\/tbody><\/table>

3. The step in glycolysis where ATP is consumed involves the enzyme:<\/p><\/td><\/tr><\/tbody><\/table>

A) Aldolase<\/p><\/td><\/tr>

C) Hexokinase<\/p><\/td><\/tr>

B) Enolase<\/p><\/td><\/tr>

D) Pyruvate kinase<\/p><\/td><\/tr><\/tbody><\/table>
\u00a0<\/td><\/tr>

4. How many ATP molecules are consumed during the energy investment phase?<\/p><\/td><\/tr><\/tbody><\/table>

A) 0<\/p><\/td><\/tr>

C) 1<\/p><\/td><\/tr>

\u00a0<\/td><\/tr>

B) 2<\/p><\/td><\/tr>

D) 4<\/p><\/td><\/tr>

\u00a0<\/td><\/tr><\/tbody><\/table>

5. What is the net gain of ATP molecules in glycolysis per glucose molecule?<\/p><\/td><\/tr><\/tbody><\/table>

A) 0<\/p><\/td><\/tr>

\u00a0<\/td><\/tr>

C) 2<\/p><\/td><\/tr>

B) 1<\/p><\/td><\/tr>

D) 4<\/p><\/td><\/tr>

\u00a0<\/td><\/tr><\/tbody><\/table>

6. What is the first irreversible step in glycolysis?<\/p><\/td><\/tr><\/tbody><\/table>

A) G \u2192 G-6-P<\/p><\/td><\/tr>

C) F-6-P \u2192 F-1,6-BP<\/p><\/td><\/tr>

B) PEP \u2192 Pyruvate<\/p><\/td><\/tr>

D) 1,3-BPG \u2192 3-PGA<\/p><\/td><\/tr><\/tbody><\/table>

7. The total number of enzymatic steps in glycolysis is:<\/p><\/td><\/tr><\/tbody><\/table>

A) 8<\/p><\/td><\/tr>

C) 9<\/p><\/td><\/tr>

B) 10<\/p><\/td><\/tr>

D) 12<\/p><\/td><\/tr><\/tbody><\/table>
\u00a0<\/td><\/tr>

8. Which step of glycolysis is regulated by feedback inhibition by ATP?<\/p><\/td><\/tr><\/tbody><\/table>

A) G \u2192 G-6-P<\/p><\/td><\/tr>

\u00a0C) F-6-P \u2192 F-1,6-BP<\/p><\/td><\/tr>

B) PEP \u2192 Pyruvate<\/p><\/td><\/tr>

D) G3P \u2192 1,3-BPG<\/p><\/td><\/tr><\/tbody><\/table>
\u00a0<\/td><\/tr>

9. The conversion of phosphoenolpyruvate to pyruvate generates:<\/p><\/td><\/tr><\/tbody><\/table>

A) NADH<\/p><\/td><\/tr>

C) FADH2<\/p><\/td><\/tr>

B) ATP<\/p><\/td><\/tr>

D) H2O<\/p><\/td><\/tr><\/tbody><\/table>
\u00a0<\/td><\/tr>

10. During glycolysis, how many NADH molecules are produced per molecule of glucose?<\/p><\/td><\/tr><\/tbody><\/table>

A) 1<\/p><\/td><\/tr>

C) 2<\/p><\/td><\/tr>

B) 4<\/p><\/td><\/tr>

D) 6<\/p><\/td><\/tr><\/tbody><\/table>
\u00a0<\/td><\/tr>

11. The glycolytic pathway is common to both:<\/p><\/td><\/tr><\/tbody><\/table>

A) Aerobic and anaerobic respiration<\/p><\/td><\/tr>

C) Photosynthesis and respiration<\/p><\/td><\/tr>

B) Gluconeogenesis and fermentation<\/p><\/td><\/tr>

D) Oxidative phosphorylation and Krebs cycle<\/p>

12. Which of the following is true about the enzyme phosphofructokinase?<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) It catalyzes the first step in glycolysis.<\/p><\/td><\/tr>

\u00a0<\/td><\/tr>

C) It converts pyruvate to phosphoenolpyruvate.<\/p><\/td><\/tr>

\u00a0<\/p>

\u00a0<\/p>

B) It is inhibited by high levels of ATP.<\/p><\/td><\/tr><\/tbody><\/table>

13. The enzyme enolase catalyzes the conversion of:<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) PEP \u2192 Pyruvate<\/p><\/td><\/tr>

C) 3-PGA \u2192 2-PGA<\/p><\/td><\/tr>

B) 2-PGA \u2192 PEP<\/p><\/td><\/tr>

D) G3P \u2192 1,3-BPG<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>
\u00a0<\/td><\/tr>

14. If one molecule of glucose undergoes glycolysis, how many pyruvate molecules are produced?<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) 1<\/p><\/td><\/tr>

C) 2<\/p><\/td><\/tr>

B) 3<\/p>

D) 4<\/p><\/td><\/tr>

\u00a0<\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

15. Identify the step where ATP is generated during glycolysis:<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) G \u2192 G-6-P<\/p><\/td><\/tr>

C) PEP \u2192 Pyruvate<\/p><\/td><\/tr>

B) F-6-P \u2192 F-1,6-BP<\/p><\/td><\/tr>

D) G3P \u2192 1,3-BPG<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>
\u00a0<\/td><\/tr>

16. In glycolysis, how many ATP molecules are consumed during the conversion of glucose to pyruvate?<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) 0<\/p><\/td><\/tr>

C) 1<\/p><\/td><\/tr>

B) 2<\/p><\/td><\/tr>

D) 4<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>
\u00a0<\/td><\/tr>
\u00a0<\/td><\/tr>

17. The first step of glycolysis that commits glucose to the glycolytic pathway is catalyzed by:<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) Hexokinase<\/p><\/td><\/tr>

B) Phosphofructokinase<\/p><\/td><\/tr>

C) Aldolase<\/p><\/td><\/tr>

D) Enolase<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>
\u00a0<\/td><\/tr>

18. Which molecule acts as the electron acceptor in glycolysis?<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) FAD<\/p><\/td><\/tr>

\u00a0B) NAD+<\/p><\/td><\/tr>

C) ATP<\/p><\/td><\/tr>

D) NADH<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

19. Which steps in glycolysis involve substrate-level phosphorylation?<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) 1,3-BPG \u2192 3-PGA; PEP \u2192 Pyruvate<\/p><\/td><\/tr>

C) F-6-P \u2192 F-1,6-BP; G-6-P \u2192 F-6-P<\/p><\/td><\/tr>

B) 1,3-BPG \u2192 3-PGA; F-1,6-BP \u2192 G3P<\/p><\/td><\/tr>

D) G3P \u2192 1,3-BPG; PEP \u2192 Pyruvate<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

———————————————————-<\/p><\/td><\/tr>

20. The splitting of fructose-1,6-bisphosphate is catalyzed by:<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

A) Phosphoglucose isomerase<\/p><\/td><\/tr>

C) Hexokinase<\/p><\/td><\/tr>

B) Aldolase<\/p><\/td><\/tr>

D) Enolase<\/p><\/td><\/tr><\/tbody><\/table>

\u00a0<\/p>

\u00a0<\/p><\/td><\/tr><\/tbody><\/table>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<\/div>\n\t\t","protected":false},"excerpt":{"rendered":"

Respiration in Plants (Glycolysis) 1. Which of the following statements about glycolysis is correct? A) Produces pyruvate C) Occurs in the cytoplasm B) Can occur anaerobically D) All of the above 2. Arrange the following intermediates of glycolysis in sequence: A) Glucose \u2192 G-6-P \u2192 F-1,6-BP \u2192 PEP\u2192 \u00a0Pyruvate C) Glucose \u2192 F-6-P \u2192 F-1,6-BP […]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"site-sidebar-layout":"no-sidebar","site-content-layout":"page-builder","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"disabled","ast-breadcrumbs-content":"","ast-featured-img":"disabled","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"class_list":["post-1286","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=\/wp\/v2\/pages\/1286","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1286"}],"version-history":[{"count":19,"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=\/wp\/v2\/pages\/1286\/revisions"}],"predecessor-version":[{"id":2359,"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=\/wp\/v2\/pages\/1286\/revisions\/2359"}],"wp:attachment":[{"href":"https:\/\/headwaytobiology.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1286"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}